Ответ:
Н2О=2+16=18
СuSO4=63+32+(16*4) =159
H2SiO3=(1*2) +28+(16*3) =78
1)H20
Mr(H20)=1*2+16=18
W(H)= 1*2/18=0,11*100%=11%
W(O)=16*1/18=0,89*100%=89%
2)CuSO4
Mr(CuSO4)=64+32+(16*4)=160
W(Cu)=64*1/160=0,40*100%=40%
W(S)=32*1/160=0,20*100%=20%
W(O)=16*4/160=0,40*100%=40%
3)H2SiO3
Mr(H2SiO3)=(1*2)+28+(16*3)=78
W(H)=1*2/78=0,03*100%=3%
W(Si)=28*1/78=0,36*100%=36%
W(O)=16*3/78=0,61*100%=61%
Объяснение:
Copyright © 2024 SCHOLAR.TIPS - All rights reserved.
Answers & Comments
Ответ:
Н2О=2+16=18
СuSO4=63+32+(16*4) =159
H2SiO3=(1*2) +28+(16*3) =78
Ответ:
1)H20
Mr(H20)=1*2+16=18
W(H)= 1*2/18=0,11*100%=11%
W(O)=16*1/18=0,89*100%=89%
2)CuSO4
Mr(CuSO4)=64+32+(16*4)=160
W(Cu)=64*1/160=0,40*100%=40%
W(S)=32*1/160=0,20*100%=20%
W(O)=16*4/160=0,40*100%=40%
3)H2SiO3
Mr(H2SiO3)=(1*2)+28+(16*3)=78
W(H)=1*2/78=0,03*100%=3%
W(Si)=28*1/78=0,36*100%=36%
W(O)=16*3/78=0,61*100%=61%
Объяснение: