Home
О нас
Products
Services
Регистрация
Войти
Поиск
vologamachalski
@vologamachalski
June 2023
1
6
Report
7. Розв'яжіть рiвняння log2(4-x) + log2(x-1) = 1
Please enter comments
Please enter your name.
Please enter the correct email address.
Agree to
terms of service
You must agree before submitting.
Send
Answers & Comments
kabuushka
log10(2(4-x))+log10(2(x-1))=1;
log10(8-2x)+log10(2x-2)=1;
log10((8-2x)•(2x-2))=1;
log10(16x-16-4x(2)+4x)=1;
16x-16-4x(2)+4x=10(1);
20x-16-4x(2)=10(1);
20x-16-4x(2)-10=0;
20x-26-4x(2)=0;
-4x(2)+20x-26=0;
2x(2)-10x+13=0;
a=2, b=-10, c=13;
x= -(-10) ± √(-10)(2)-4•2•13
/2•2;
х=10 ± √100-104
/4;
х=10 ±√-4 /4.
2 votes
Thanks 0
More Questions From This User
See All
vologamachalski
May 2023 | 0 Ответы
2 i ii i 1000 b
Answer
vologamachalski
July 2022 | 0 Ответы
texkak zamest a podstavit 6
Answer
vologamachalski
October 2021 | 0 Ответы
2pomogite mne ya tupoj
Answer
vologamachalski
September 2021 | 0 Ответы
6 kor 2 kor 2 2
Answer
×
Report "7. Розв'яжіть рiвняння log2(4-x) + log2(x-1) = 1 "
Your name
Email
Reason
-Select Reason-
Pornographic
Defamatory
Illegal/Unlawful
Spam
Other Terms Of Service Violation
File a copyright complaint
Description
Helpful Links
О нас
Политика конфиденциальности
Правила и условия
Copyright
Контакты
Helpful Social
Get monthly updates
Submit
Copyright © 2025 SCHOLAR.TIPS - All rights reserved.
Answers & Comments
log10(8-2x)+log10(2x-2)=1;
log10((8-2x)•(2x-2))=1;
log10(16x-16-4x(2)+4x)=1;
16x-16-4x(2)+4x=10(1);
20x-16-4x(2)=10(1);
20x-16-4x(2)-10=0;
20x-26-4x(2)=0;
-4x(2)+20x-26=0;
2x(2)-10x+13=0;
a=2, b=-10, c=13;
x= -(-10) ± √(-10)(2)-4•2•13
/2•2;
х=10 ± √100-104
/4;
х=10 ±√-4 /4.