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dthbj
@dthbj
July 2022
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Решите неравенство f'(x)>0 б)f(x)=x^3/3-x^2+2 г)f(x)=-x^3/3-1/2x^2+6/7 ПОМОГИТЕ ПОЖАЛУЙСТАА
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sedinalana
Verified answer
1
f`(x)=x²-2x
x(x-2)>0
x=0 U x=2
x∈(-∞;0) U (2;∞)
2
f`(x)=x²-x
x(x-1)=0
x=0 U x=1
x∈(-∞;0) U (1;∞)
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Verified answer
1f`(x)=x²-2x
x(x-2)>0
x=0 U x=2
x∈(-∞;0) U (2;∞)
2
f`(x)=x²-x
x(x-1)=0
x=0 U x=1
x∈(-∞;0) U (1;∞)