cos0+cospi/7+cos2pi/7+cos3pi/7+cos4pi/7+cos5pi/7+cos6pi/7 упростить помогите
cos0 + [cos(6π/7)+cos(π/7)] + [cos(5π/7)+cos(2π/7)] + [cos(4π/7)+cos(3π/7)] =
1 +2cos(π/2)cos(5π/7) + 2cos(π/2)cos(3π/2) + 2cos(π/2)cos(π/2) = 1
cos0=1,
cospi/7+cos2pi/7+cos3pi/7+cos4pi/7+cos5pi/7+cos6pi/7=cos21pi/7=cos3pi=cos(2pi+pi)=cospi=-1,
Теперь подставляем,получается
1-1=0
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Answers & Comments
cos0 + [cos(6π/7)+cos(π/7)] + [cos(5π/7)+cos(2π/7)] + [cos(4π/7)+cos(3π/7)] =
1 +2cos(π/2)cos(5π/7) + 2cos(π/2)cos(3π/2) + 2cos(π/2)cos(π/2) = 1
Verified answer
cos0=1,
cospi/7+cos2pi/7+cos3pi/7+cos4pi/7+cos5pi/7+cos6pi/7=cos21pi/7=cos3pi=cos(2pi+pi)=cospi=-1,
Теперь подставляем,получается
1-1=0