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839010
@839010
August 2022
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7. Яке число молекул містить водень Н2 об’ємом 448 л (н.у.)?
А 6,02·10^23 Б 3,01·10^23 В 0,602·10^23 Г 60,2·10^23.
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tanyacool
Verified answer
N=Na*n=Na*V/Vm=6,02*10²³*448/22,4=120,4·10²³ молекул получается
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N=Na*n=Na*V/Vm=6,02*10²³*448/22,4=120,4·10²³ молекул получается