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SwagVi
@SwagVi
October 2021
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7 задание...объясните как
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m11m
a² -9b²
*
a
=
(a-3b)(a+3b)
*
1
=
a-3b
=
a
-
3b
= 1 -
3b
a² a+3b a a+3b a a a a
При а=√5 и b=√125
1 -
3*√125
= 1 -
3 √(5*25)
= 1 -
3*√5 * √25
=1 - 3*5 = 1-15= -14
√5 √5 √5
Ответ: -14
0 votes
Thanks 1
Larisaremizowa
А²-9в² /а²×а/а+3в=(а-3в)(а+3в)×а/а²(а+3в)=а-3в /а
подставим значения а=√5, в=√125
√5-3√125 /√5=√5-15√5 /√5=-14√5/√5=-14
0 votes
Thanks 1
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Answers & Comments
a² a+3b a a+3b a a a a
При а=√5 и b=√125
1 - 3*√125 = 1 - 3 √(5*25) = 1 - 3*√5 * √25 =1 - 3*5 = 1-15= -14
√5 √5 √5
Ответ: -14
подставим значения а=√5, в=√125
√5-3√125 /√5=√5-15√5 /√5=-14√5/√5=-14