Verified answer

[tex]6\frac{1}{9}(t-9)+2\frac{5}{9} (18-t)=6\frac{1}{9}t-\frac{55*9}{9} +\frac{23*18}{9} -2\frac{5}{9}t=5\frac{10}{9}t-2\frac{5}{9}t-55+46=3\frac{5}{9} t-9=3\frac{5}{9}*(-0,2)-9=-\frac{32}{9*5} -9=-\frac{32}{45} -9=-9\frac{32}{45}[/tex]

Пошаговое объяснение:

6 1/9(t - 9) + 2 5/9(18 - t) =

55/9(t - 9) + 23/9(18 - t) =

55/9t - 55 + 46 - 23/9t =

(55/9t - 23/9t) + (-55 + 46) =

32/9t + (-9) = 32/9t - 9

t = -0,2

32/9t - 9 = 32/9 * (-0,2) - 9 = 32/9 * (-2/10) - 9 =

-64/90 - 9 = -32/45 - 9 = -9 32/45