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manasyanlilit
@manasyanlilit
November 2021
1
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объясните как решать..
2/7:8+5:0,7-3/4:21
3:4 целых 1/5+5,4:7,2-2/7:0,8
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AS02
2/7:8+5:0,7-3/4:21=2/7:8/1+5/1:7/10-3/4:21/1=(2*1)/(7*8)+(5*10)/(7*1)-(3*1)/(4*21)=
2/(7*2*2*2)+50/7-3/(2*2*3*7)=(2*3)/(7*2*2*2*3)+(50*2*2*2*3)/(7*2*2*2*3)-
-(3*2)/(7*2*2*2*3)=(6+50*2*2*2*3-6)/(7*2*2*2*3)=50/7=7 1/7
2 votes
Thanks 2
manasyanlilit
а где кончается 1??
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Answers & Comments
2/(7*2*2*2)+50/7-3/(2*2*3*7)=(2*3)/(7*2*2*2*3)+(50*2*2*2*3)/(7*2*2*2*3)-
-(3*2)/(7*2*2*2*3)=(6+50*2*2*2*3-6)/(7*2*2*2*3)=50/7=7 1/7