Verified answer

Ответ:

[tex]\tt\displaystyle \bold{\sqrt{b} }[/tex]

Объяснение:

[tex]\tt\displaystyle \frac{a}{\sqrt{b}-\sqrt{a} } :(\frac{\sqrt{b} }{\sqrt{b}-\sqrt{a} }-\frac{\sqrt{b}+\sqrt{a} }{\sqrt{b} } )=\\\\\\=\frac{a}{\sqrt{b}-\sqrt{a} } :(\frac{\sqrt{b}*\sqrt{b} -(\sqrt{b}+\sqrt{a})(\sqrt{b}-\sqrt{a})}{(\sqrt{b}-\sqrt{a} )*\sqrt{b} })=\\\\\\=\frac{a}{\sqrt{b}-\sqrt{a} } :(\frac{b-(b-a)}{(\sqrt{b}-\sqrt{a} )*\sqrt{b}} )=\\\\\\=\frac{a}{\sqrt{b}-\sqrt{a} } :(\frac{b-b+a}{(\sqrt{b}-\sqrt{a} )*\sqrt{b}} )=[/tex]

[tex]\tt\displaystyle =\frac{a}{\sqrt{b}-\sqrt{a} } *\frac{(\sqrt{b}-\sqrt{a} )*\sqrt{b}}{a} =\\\\\\=\sqrt{b}[/tex]