C12H22O11 + H2O = C6H12O6 + C6H12O6
n(C12H22O11)=72/342=0.21
n(C6H12O6)=0.2 1
m(C6H12O6 теор) =0.21*180=37.8
m(C6H12O6 практ) =37.8*0.9=34,02
Ответ: 34,02 г
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C12H22O11 + H2O = C6H12O6 + C6H12O6
n(C12H22O11)=72/342=0.21
n(C6H12O6)=0.2 1
m(C6H12O6 теор) =0.21*180=37.8
m(C6H12O6 практ) =37.8*0.9=34,02
Ответ: 34,02 г