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arukaorange
@arukaorange
March 2023
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№729 помогите срочно
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fenix6810
Verified answer
16cos4acos2acosasina=8cos4acos2asin2a=4cos4asin4a=2sin8a
(cosa-sina)(cosa+sina(1-cosasina)=cos2a(1-1/2sin2a)
(sin^2a+co^2a)^2-2sin^2acos^2a-1/4cos4a=1-1/2sin^22a-1/4(1-2sin^22a)=3/4
(cos^2a+sin^2a)^2-8cos^2asin^2a=1-2sin^2(2a)=cos4a
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Answers & Comments
Verified answer
16cos4acos2acosasina=8cos4acos2asin2a=4cos4asin4a=2sin8a
(cosa-sina)(cosa+sina(1-cosasina)=cos2a(1-1/2sin2a)
(sin^2a+co^2a)^2-2sin^2acos^2a-1/4cos4a=1-1/2sin^22a-1/4(1-2sin^22a)=3/4
(cos^2a+sin^2a)^2-8cos^2asin^2a=1-2sin^2(2a)=cos4a