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viqsep5sqct
@viqsep5sqct
August 2022
1
1
Report
7(2x–5)²–2(7x–1)²=
(4y²+3)²+(9–4y²)²–2(4y²+3)(4y²–9)=
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crezychamomile
Вроде бы так,насколько я знаю
1 votes
Thanks 2
viqsep5sqct
видимо я неправильно пояснила. тут два номера...
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