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kotenokmaili
@kotenokmaili
June 2021
2
18
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№732 (3,4,5,6) с решением пожалуйста
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k43ff
Тут все решаеться так: log(a)b=c b=a^c
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sedinalana
3
ОДЗ x>0
log(1/3)x=log(1/3)49
x=49
4
ОДЗ x>1
log(0,2)(x-1)=4
x-1=0,0016
x=1,0016
5
ОДЗ x(x+7)>0⇒x<-7 U x>1
log(5)log(3)log(2)(x²+7x)=0
log(3)log(2)(x²+7x)=1
log(2)(x²+7x)=3
x²+7x=8
x²+7x-8=0
x1+x2=-7 U x1*x2=-8
x1=-8 U x2=1
6
ОДЗ x>0
log(4)log(2)x=1/2
log(2)x=2
x=4
0 votes
Thanks 0
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Answers & Comments
ОДЗ x>0
log(1/3)x=log(1/3)49
x=49
4
ОДЗ x>1
log(0,2)(x-1)=4
x-1=0,0016
x=1,0016
5
ОДЗ x(x+7)>0⇒x<-7 U x>1
log(5)log(3)log(2)(x²+7x)=0
log(3)log(2)(x²+7x)=1
log(2)(x²+7x)=3
x²+7x=8
x²+7x-8=0
x1+x2=-7 U x1*x2=-8
x1=-8 U x2=1
6
ОДЗ x>0
log(4)log(2)x=1/2
log(2)x=2
x=4