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rasko1nikov
@rasko1nikov
July 2022
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kedr57
Verified answer
FeCln+nAgNO3=nAgCl+Fe(NO3)n
Mr(FeCln)=56+35,5n
Mr(AgNO3)=108+14+48=170 cоставим пропорцию
1,6------------- 4,2
56+35,5n-----170n 1,6×170n=4,2(56+35,5n) отсюда n=2 FeCl2 cтепень окисления железа равна
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Verified answer
FeCln+nAgNO3=nAgCl+Fe(NO3)nMr(FeCln)=56+35,5n
Mr(AgNO3)=108+14+48=170 cоставим пропорцию
1,6------------- 4,2
56+35,5n-----170n 1,6×170n=4,2(56+35,5n) отсюда n=2 FeCl2 cтепень окисления железа равна 2