Ответ:
Объяснение:
2 1) [tex]x^{2}-81=(x-9)(x+9)[/tex]
2) [tex]25-9a^{2}=(5-3a)(5+3a)[/tex]
3) [tex]36x^{2}-100y^{2}=(6x-10y)(6x+10y)[/tex]
4) [tex]0,04x^{2}-1,69y^{2}=(0,2x-1,3y)(0,2x+1,3y)[/tex]
5) [tex]x^{2}y^{2}-\frac{4}{25}=(xy+\frac{2}{5})(xy-\frac{2}{5})[/tex]
1 1) [tex](x-y)(x+y)=x^{2}-y^{2}[/tex]
2) [tex](13+x)(x-13)=x^{2}-169[/tex]
3) [tex](2x-7)(2x+7)=4x^{2}-49[/tex]
4) [tex](x^{3}+a^{2})(-x^{3}+a^{2})=a^{4}-x^{6}[/tex]
5) [tex](0,2x-0,3)(0,2x+0,3)=0,04x^{2}-0,09[/tex]
6) [tex](\frac{3}{8}x^{2}-\frac{1}{9})(\frac{3}{8}x^{2}+\frac{1}{9})=\frac{9}{64}x^{4}-\frac{1}{81}[/tex]
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Answers & Comments
Ответ:
Объяснение:
2 1) [tex]x^{2}-81=(x-9)(x+9)[/tex]
2) [tex]25-9a^{2}=(5-3a)(5+3a)[/tex]
3) [tex]36x^{2}-100y^{2}=(6x-10y)(6x+10y)[/tex]
4) [tex]0,04x^{2}-1,69y^{2}=(0,2x-1,3y)(0,2x+1,3y)[/tex]
5) [tex]x^{2}y^{2}-\frac{4}{25}=(xy+\frac{2}{5})(xy-\frac{2}{5})[/tex]
1 1) [tex](x-y)(x+y)=x^{2}-y^{2}[/tex]
2) [tex](13+x)(x-13)=x^{2}-169[/tex]
3) [tex](2x-7)(2x+7)=4x^{2}-49[/tex]
4) [tex](x^{3}+a^{2})(-x^{3}+a^{2})=a^{4}-x^{6}[/tex]
5) [tex](0,2x-0,3)(0,2x+0,3)=0,04x^{2}-0,09[/tex]
6) [tex](\frac{3}{8}x^{2}-\frac{1}{9})(\frac{3}{8}x^{2}+\frac{1}{9})=\frac{9}{64}x^{4}-\frac{1}{81}[/tex]