Ответ:

[tex] \sqrt{3} \tan(60) - \sqrt{2} \sin(45) = \sqrt{3} \times \sqrt{ 3} - \sqrt{2} \times \frac{ \sqrt{2} }{2} = ( { \sqrt{3} })^{2} - \frac{( { \sqrt{2} })^{2} }{ \times 2} = 3 - \frac{2}{2} = 3 - 1 = 2[/tex]