[tex]\displaystyle \frac{75^2-35^2}{63^2-23^2}=\frac{(75-35)(75+35)}{(63-23)(63+23)}=\frac{40*110}{40*86}=\frac{4400}{3440}=\frac{55}{43}=1\frac{12}{43}[/tex]

Verified answer

Пошаговое объяснение:

[tex] \displaystyle \frac{ {75}^{2} - {35}^{2} }{ {63}^{2} - {23}^{2} } = \frac{(75 + 35)(75 - 35)}{(63 + 23)(63 - 23)} = \frac{110 \times 40}{86 \times 40} = \frac{110}{86} = \frac{55}{43} = 1 \frac{12}{43} .[/tex]