[tex]1) \: \: \: \: \: - 11 {a}^{2} b \times 0.3 {a}^{2} {b}^{2} = - 3.3 {a}^{4} {b}^{3} [/tex]
[tex]2) \: \: \: \: \: \frac{4}{9} {xy}^{2} \times \frac{2}{3} xy = \frac{8}{27} {x}^{2} {y}^{3} \\ [/tex]
[tex]3) \: \: \: \: \: - 0.6 {m}^{2} n \times ( - 10 {mn}^{2} ) = 6 {m}^{3} {n}^{3} [/tex]
[tex]4) \: \: \: \: \: {x}^{5} y \times x {y}^{3} z = {x}^{6} {y}^{4} z[/tex]
[tex]5) \: \: \: \: \: - 4ab \times ( - {a}^{2} ) \times ( - {b}^{2} ) = - 4 {a}^{3} {b}^{3} [/tex]
[tex]6) \: \: \: \: \: - \frac{1}{5} {p}^{3} {q}^{4} \times 5 {p}^{2} {q}^{3} = - {p}^{5} {q}^{7} \\ [/tex]
Copyright © 2024 SCHOLAR.TIPS - All rights reserved.
Answers & Comments
Verified answer
[tex]1) \: \: \: \: \: - 11 {a}^{2} b \times 0.3 {a}^{2} {b}^{2} = - 3.3 {a}^{4} {b}^{3} [/tex]
[tex]2) \: \: \: \: \: \frac{4}{9} {xy}^{2} \times \frac{2}{3} xy = \frac{8}{27} {x}^{2} {y}^{3} \\ [/tex]
[tex]3) \: \: \: \: \: - 0.6 {m}^{2} n \times ( - 10 {mn}^{2} ) = 6 {m}^{3} {n}^{3} [/tex]
[tex]4) \: \: \: \: \: {x}^{5} y \times x {y}^{3} z = {x}^{6} {y}^{4} z[/tex]
[tex]5) \: \: \: \: \: - 4ab \times ( - {a}^{2} ) \times ( - {b}^{2} ) = - 4 {a}^{3} {b}^{3} [/tex]
[tex]6) \: \: \: \: \: - \frac{1}{5} {p}^{3} {q}^{4} \times 5 {p}^{2} {q}^{3} = - {p}^{5} {q}^{7} \\ [/tex]