Home
О нас
Products
Services
Регистрация
Войти
Поиск
Dianatim1
@Dianatim1
July 2022
1
6
Report
7cos^2x+5cosx*sinx-1=0
Please enter comments
Please enter your name.
Please enter the correct email address.
Agree to
terms of service
You must agree before submitting.
Send
Answers & Comments
hlopushinairina
7cos²x+5cosx·sinx-1=0;⇒
7cos²x+5cosx·sinx-cos²x-sin²x=0;⇒6cos²x+5cosx·sinx-sin²x=0;
все слагаемые поделить на cos²x:
6+5tgx-tg²x=0;⇒tgx=y;⇒y²-5y-6=0;⇒
y₁₂=5/2⁺₋√25/4+6=5/2⁺₋7/2;
y₁=5/2+7/2=6;⇒tgx=6;x=arctg6+kπ;k∈Z;
y₂=5/2-7/2=-1;⇒tgx=-1;x=-π/4+kπ;k∈Z;
1 votes
Thanks 2
More Questions From This User
See All
Dianatim1
July 2022 | 0 Ответы
sinxcos3xcosxsin3x1 pozhalujsta
Answer
Dianatim1
July 2022 | 0 Ответы
sinxcos5x=sin9xcos3x...
Answer
Dianatim1
July 2022 | 0 Ответы
pozhalujstasrochno nado napisat nebolshoe esse po citate chelovek prednaznachen
Answer
Dianatim1
July 2022 | 0 Ответы
3,x0=1...
Answer
рекомендуемые вопросы
rarrrrrrrr
August 2022 | 0 Ответы
o chem dolzhny pozabotitsya v pervuyu ochered vzroslye pri organizacionnom vyvoze n
danilarsentev
August 2022 | 0 Ответы
est dva stanka na kotoryh vypuskayut odinakovye zapchasti odin proizvodit a zapcha
myachina8
August 2022 | 0 Ответы
najti po grafiku otnoshenie v3v1 v otvetah napisano 9 no nuzhno reshenie
ydpmn7cn6w
August 2022 | 0 Ответы
Choose the correct preposition: 1.I am fond (out,of,from) literature. 2.where ar...
millermilena658
August 2022 | 0 Ответы
opredelite kak sozdavalas i kto sozdaval arabskoe gosudarstvo v kracii
MrZooM222
August 2022 | 0 Ответы
ch ajtmanov v rasskaze krasnoe yabloko ispolzuet metod rasskaz v rasskaze opi
timobila47
August 2022 | 0 Ответы
kakovo bylo naznachenie kazhdoj iz chastej vizantijskogo hrama pomogite pozhalujsta
ivanyyaremkiv
August 2022 | 0 Ответы
moment. 6....
pozhalujsta8b98a56c0152a07b8f4cbcd89aa2f01e 97513
sarvinozwakirjanova
August 2022 | 0 Ответы
pomogite pozhalusto pzha519d7eb8246a08ab0df06cc59e9dedb 6631
×
Report "7cos^2x+5cosx*sinx-1=0..."
Your name
Email
Reason
-Select Reason-
Pornographic
Defamatory
Illegal/Unlawful
Spam
Other Terms Of Service Violation
File a copyright complaint
Description
Helpful Links
О нас
Политика конфиденциальности
Правила и условия
Copyright
Контакты
Helpful Social
Get monthly updates
Submit
Copyright © 2025 SCHOLAR.TIPS - All rights reserved.
Answers & Comments
7cos²x+5cosx·sinx-cos²x-sin²x=0;⇒6cos²x+5cosx·sinx-sin²x=0;
все слагаемые поделить на cos²x:
6+5tgx-tg²x=0;⇒tgx=y;⇒y²-5y-6=0;⇒
y₁₂=5/2⁺₋√25/4+6=5/2⁺₋7/2;
y₁=5/2+7/2=6;⇒tgx=6;x=arctg6+kπ;k∈Z;
y₂=5/2-7/2=-1;⇒tgx=-1;x=-π/4+kπ;k∈Z;