(7+d)*(d-7)+(d+3)*(3-d)+40*(d+1)при d=0.5. Created by erddgf. algebra-ru

(7+d)*(d-7)+(d+3)*(3-d)+40*(d+1)при d=0.5...

erddgf @erddgf

July 2022 1 3 Report

(7+d)*(d-7)+(d+3)*(3-d)+40*(d+1)при d=0.5

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(7 + d)(d - 7) + (d + 3)(3 - d) + 40(d + 1) = (d + 7)(d - 7) + (3 + d)(3 - d) +
+ 40(d + 1) = d² - 49 + 9 - d² + 40d + 40 = 40d
Если d = 0,5 , то 40 * 0,5 = 20

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7dd 7d33 d40d1pri d05f99191230f63632c5e765af9387a2ba7 14156

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7dd 7d33 d40d1pri d05f99191230f63632c5e765af9387a2ba7 14156

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