Ответ:
[tex]\displaystyle 4)\frac{x-5}{x};\\5) -3[/tex]
Объяснение:
[tex]4)[/tex] сократим дробь[tex]\displaystyle \frac{5x^{2}-3x-2 }{5x^{2} +2x}[/tex].
[tex]\displaystyle 5)\frac{x+9}{x-3} -\frac{6}{x^{2} -9} \div\frac{6}{(x+3)^{2} } -\frac{3x-3}{x-3} =\frac{x+9}{x-3} -\frac{6}{(x-3)(x+3)} \cdot\frac{(x+3)^{2} }{6} -\frac{3x-3}{x-3} =\frac{x+9}{x-3} -\frac{x+3}{x-3} -\frac{3x-3}{x-3}=\frac{x+9-(x-3)-(3x-3)}{x-3} =\frac{x+9-x+3-3x+3}{x-3} =\frac{-3x+15}{x-3} =\frac{-3(x-3)}{x-3} =-3[/tex]
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Answers & Comments
Ответ:
[tex]\displaystyle 4)\frac{x-5}{x};\\5) -3[/tex]
Объяснение:
[tex]4)[/tex] сократим дробь[tex]\displaystyle \frac{5x^{2}-3x-2 }{5x^{2} +2x}[/tex].
[tex]\displaystyle 5)\frac{x+9}{x-3} -\frac{6}{x^{2} -9} \div\frac{6}{(x+3)^{2} } -\frac{3x-3}{x-3} =\frac{x+9}{x-3} -\frac{6}{(x-3)(x+3)} \cdot\frac{(x+3)^{2} }{6} -\frac{3x-3}{x-3} =\frac{x+9}{x-3} -\frac{x+3}{x-3} -\frac{3x-3}{x-3}=\frac{x+9-(x-3)-(3x-3)}{x-3} =\frac{x+9-x+3-3x+3}{x-3} =\frac{-3x+15}{x-3} =\frac{-3(x-3)}{x-3} =-3[/tex]