Ответ: ≈1.4848

Объяснение:

1/log(5;3)=log(3;5)= log(2;5) / log(2;3)

[tex]log(2;5)=\frac{1}{3} *log(2;5^3) =\frac{1}{3}*log(2;125)=\frac{1}{3}*7=7/3[/tex]

[tex]log(2;3)=\frac{1}{7}*log(2;3^7)= \frac{1}{7}*log(2;2187)=\frac{1}{7}*11=\frac{11}{7}[/tex]

log(3;5)=(7/3):(11/7)≈ 49/33 ≈1.4848