Ответ:
:)
Объяснение:
5. 1/а3
6. [tex]\sqrt{49b} - 0,5\sqrt{64b} \\7\sqrt{b}-4\sqrt{b}=3\sqrt{b}[/tex]
7.
[tex]3x^{2} -10x+3=0\\\\x1,x2=\frac{5+-\sqrt{25-9} }{3} =\frac{5+-4}{3} \\\\X1=3 x2=\frac{1}{3}[/tex]
8.
[tex](\frac{x-2}{x+2} - \frac{x+2}{x-2} ) :\frac{8x}{x^{2} -4} \\(\frac{(x-2)^{2-(x+2)^{2} } }{x^{2} -4} ):\frac{8x}{x^{2} -4} \\\\\frac{x^{2}-4x+4-x^{2} -4x-4 }{x^{2} -4} :\frac{8x}{x^{2} -4} \\\\\\\frac{-(8x)}{x^{2} -4} *\frac{x^{2} -4}{8x} \\\\\\=-1[/tex]
9. не знаю сорі
10.
.[tex]\sqrt{(\sqrt{14}-3) ^{2} } -\sqrt{(\sqrt{14}-4) ^{2} }\\\sqrt{14}-3 -(\sqrt{14}-4)\\\sqrt{14}-3 -4\sqrt{14}\\\\2\sqrt{14} -7[/tex]
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Verified answer
Ответ:
:)
Объяснение:
5. 1/а3
6. [tex]\sqrt{49b} - 0,5\sqrt{64b} \\7\sqrt{b}-4\sqrt{b}=3\sqrt{b}[/tex]
7.
[tex]3x^{2} -10x+3=0\\\\x1,x2=\frac{5+-\sqrt{25-9} }{3} =\frac{5+-4}{3} \\\\X1=3 x2=\frac{1}{3}[/tex]
8.
[tex](\frac{x-2}{x+2} - \frac{x+2}{x-2} ) :\frac{8x}{x^{2} -4} \\(\frac{(x-2)^{2-(x+2)^{2} } }{x^{2} -4} ):\frac{8x}{x^{2} -4} \\\\\frac{x^{2}-4x+4-x^{2} -4x-4 }{x^{2} -4} :\frac{8x}{x^{2} -4} \\\\\\\frac{-(8x)}{x^{2} -4} *\frac{x^{2} -4}{8x} \\\\\\=-1[/tex]
9. не знаю сорі
10.
.[tex]\sqrt{(\sqrt{14}-3) ^{2} } -\sqrt{(\sqrt{14}-4) ^{2} }\\\sqrt{14}-3 -(\sqrt{14}-4)\\\sqrt{14}-3 -4\sqrt{14}\\\\2\sqrt{14} -7[/tex]