Home
О нас
Products
Services
Регистрация
Войти
Поиск
isazhanq
@isazhanq
July 2022
1
15
Report
7^(log по основанию(7) числа 4)-4^(x^2+2)=1
Please enter comments
Please enter your name.
Please enter the correct email address.
Agree to
terms of service
You must agree before submitting.
Send
Answers & Comments
джек005
11)4^x-4^(x²+x)=4^0
x²=0,x=0
12) 6/(2x-5)=2/(5-x)
2*(2x-5)=6*(5-x)
4x-10=30-6x
10x=40
x=4
13) √(x-2)=x-8
x-2=x²-16x+64
x²-17x+66=0
D=b²−4ac =(−17)²−4⋅1⋅66=25
x1=−b+√D/2a=
17+√25/2 =11
x2=−b−√D/2a=
17−√25/2 =6
√(11-2)=11-8
√9=3
3=3
√(6-3)=6-8
√3=-2
ответ 6-не имеет значения
0 votes
Thanks 0
More Questions From This User
See All
isazhanq
July 2022 | 0 Ответы
a esli obem iskat
Answer
рекомендуемые вопросы
rarrrrrrrr
August 2022 | 0 Ответы
o chem dolzhny pozabotitsya v pervuyu ochered vzroslye pri organizacionnom vyvoze n
danilarsentev
August 2022 | 0 Ответы
est dva stanka na kotoryh vypuskayut odinakovye zapchasti odin proizvodit a zapcha
myachina8
August 2022 | 0 Ответы
najti po grafiku otnoshenie v3v1 v otvetah napisano 9 no nuzhno reshenie
ydpmn7cn6w
August 2022 | 0 Ответы
Choose the correct preposition: 1.I am fond (out,of,from) literature. 2.where ar...
millermilena658
August 2022 | 0 Ответы
opredelite kak sozdavalas i kto sozdaval arabskoe gosudarstvo v kracii
MrZooM222
August 2022 | 0 Ответы
ch ajtmanov v rasskaze krasnoe yabloko ispolzuet metod rasskaz v rasskaze opi
timobila47
August 2022 | 0 Ответы
kakovo bylo naznachenie kazhdoj iz chastej vizantijskogo hrama pomogite pozhalujsta
ivanyyaremkiv
August 2022 | 0 Ответы
moment. 6....
pozhalujsta8b98a56c0152a07b8f4cbcd89aa2f01e 97513
sarvinozwakirjanova
August 2022 | 0 Ответы
pomogite pozhalusto pzha519d7eb8246a08ab0df06cc59e9dedb 6631
×
Report "7^(log по основанию(7) числа 4)-4^(x^2+2)=1..."
Your name
Email
Reason
-Select Reason-
Pornographic
Defamatory
Illegal/Unlawful
Spam
Other Terms Of Service Violation
File a copyright complaint
Description
Helpful Links
О нас
Политика конфиденциальности
Правила и условия
Copyright
Контакты
Helpful Social
Get monthly updates
Submit
Copyright © 2024 SCHOLAR.TIPS - All rights reserved.
Answers & Comments
x²=0,x=0
12) 6/(2x-5)=2/(5-x)
2*(2x-5)=6*(5-x)
4x-10=30-6x
10x=40
x=4
13) √(x-2)=x-8
x-2=x²-16x+64
x²-17x+66=0
D=b²−4ac =(−17)²−4⋅1⋅66=25
x1=−b+√D/2a=
17+√25/2 =11
x2=−b−√D/2a=
17−√25/2 =6
√(11-2)=11-8
√9=3
3=3
√(6-3)=6-8
√3=-2
ответ 6-не имеет значения