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isazhanq
@isazhanq
July 2022
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7^(log по основанию(7) числа 4)-4^(x^2+2)=1
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джек005
11)4^x-4^(x²+x)=4^0
x²=0,x=0
12) 6/(2x-5)=2/(5-x)
2*(2x-5)=6*(5-x)
4x-10=30-6x
10x=40
x=4
13) √(x-2)=x-8
x-2=x²-16x+64
x²-17x+66=0
D=b²−4ac =(−17)²−4⋅1⋅66=25
x1=−b+√D/2a=
17+√25/2 =11
x2=−b−√D/2a=
17−√25/2 =6
√(11-2)=11-8
√9=3
3=3
√(6-3)=6-8
√3=-2
ответ 6-не имеет значения
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Answers & Comments
x²=0,x=0
12) 6/(2x-5)=2/(5-x)
2*(2x-5)=6*(5-x)
4x-10=30-6x
10x=40
x=4
13) √(x-2)=x-8
x-2=x²-16x+64
x²-17x+66=0
D=b²−4ac =(−17)²−4⋅1⋅66=25
x1=−b+√D/2a=
17+√25/2 =11
x2=−b−√D/2a=
17−√25/2 =6
√(11-2)=11-8
√9=3
3=3
√(6-3)=6-8
√3=-2
ответ 6-не имеет значения