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Vladuss1337
@Vladuss1337
July 2022
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35^n/7^n+1*5^n-1 решить
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konstantsya
35^n/(7^(n+1)*5^(n-1 ))= (5^n*7^n)/((7^n* 7^1)*5^n*5^(-1) ))=5/7
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