q=3/7,S=42..найти :с1,где сумма Sбесконечности
q=3/7
S=42
c1-?
S=c1/(1-q)
42=c1/(1-3/7)
c1/(4/7)=42
c1=24
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q=3/7
S=42
c1-?
S=c1/(1-q)
42=c1/(1-3/7)
c1/(4/7)=42
c1=24