решите линейное уравнение
а)1/3x= 12
б) 2/3y=9
в)-4x=1/7
г) 5y= - 5/8
д) 1/6 y= 1/3
e) 2/7x = 0
а)1/3x= 12
б) 2/3y=9
в)-4x=1/7
г) 5y= - 5/8
д) 1/6 y= 1/3
e) 2/7x = 0
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а)1/3x= 12х = 12 : 1\3
х = 12 * 3
х = 36
б) 2/3y=9
у = 9 : 2/3
у = 9 * 3/2
у = 27/2
у = 13,5
в)-4x=1/7
х = 1/7 : (-4)
х = 1/7 * (- 1/4)
х = - 1/28
г) 5y= - 5/8
у = - 5/8 : 5
у = - 5/8 * 1/5
у = - 1/8
д) 1/6 y= 1/3
у = 1/3 : 1/6
у = 1/3 * 6/1
у = 2
e) 2/7x = 0
х = 0 : 2/7
х = 0