Срочно!!!!!!!!!!Даю 50 баллов!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!Найди наименьшее значение функции y=−1/7x2+5 на отрезке [−8;7].
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(-x)²=x²≥0 , x∈R
(-1/7)x²≤0
(-1/7)x²+5≤5
(-8)²=64, 7²=49
(-1/7)(-8)²+5=(-1/7)(64)+5=-64/7+5=-64/7+35/7=-29/7
y=-29/7, x=-8