Подайте добуток у вигляді многочлена:
1) (m – n)(m+n);
2) (3m - n)(3m + n);
3) (5x - 7y)(5x + 7y);
4) (6x - 3y²)(6x + 3y²);
5) (8x - y³)(8x +у³);
6) (0,5x -y)(0,5x+y);
7) (−3m - n)( −3m + n);
8) (m – 1/3n)(m + 1/3n);
9) (2/7x-y)(2/7x+y);
10) (1,6x + 3y²)(1,6x - 3y²);
11) (80x - y⁵)(80x + y⁵);
12) (2,5x⁶-y)(2,5x⁶+y).
1) (m – n)(m+n);
2) (3m - n)(3m + n);
3) (5x - 7y)(5x + 7y);
4) (6x - 3y²)(6x + 3y²);
5) (8x - y³)(8x +у³);
6) (0,5x -y)(0,5x+y);
7) (−3m - n)( −3m + n);
8) (m – 1/3n)(m + 1/3n);
9) (2/7x-y)(2/7x+y);
10) (1,6x + 3y²)(1,6x - 3y²);
11) (80x - y⁵)(80x + y⁵);
12) (2,5x⁶-y)(2,5x⁶+y).
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Answers & Comments
Объяснение:
[tex]1) \: (m \: - n)(m \: + n) = {m}^{2} - {n}^{2} [/tex]
[tex]2) \: (3m - n)(3m + n) = {9m}^{2} - {n}^{2} [/tex]
[tex]3) \: (5x - 7y)(5x + 7y) = {25x}^{2} - {49y}^{2} [/tex]
[tex]4) \: (6x - 3y²)(6x + 3y²) = {36x}^{2} - {9y}^{4} [/tex]
[tex]5) \: (8x - y³)(8x +у³) = {64x}^{2} - {y}^{6} [/tex]
[tex]6) \: (0,5x -y)(0,5x+y) = {0,25x}^{2} - {y}^{2} [/tex]
[tex]7) \: (−3m - n)( −3m + n) = {9m}^{2} - {n}^{2}[/tex]
[tex][8) \: (m – \frac{1}{3} n)(m + \frac{1}{3} n) = {m}^{2} - \frac{2}{6} {n}^{2}[/tex]
[tex]9) \: ( \frac{2}{7} x-y)( \frac{2}{7} x+y) = \frac{4}{14} {x}^{2} - {y}^{2} [/tex]
[tex]10) \: (1,6x + 3y²)(1,6x - 3y²) = {2,56x}^{2} - {9y}^{4} [/tex]
[tex]11) \: (80x - y⁵)(80x + y⁵) = {6400x}^{2} - {y}^{10} [/tex]
[tex]12) \: (2,5x⁶-y)(2,5x⁶+y) = {6,25x}^{12} - {y}^{2} [/tex]