Ответ:
2.
[tex]( \frac{ {a}^{2}b^{3} }{3c ^{5} } ) ^{4} = \frac{ {a}^{8} {b}^{12} }{81 {c}^{20} } [/tex]
3.
[tex] \frac{ {x}^{2} - 4x }{8 {x}^{2} } \div \frac{x - 4}{4x} = \frac{ x(x - 4) }{8 {x}^{2} } \times \frac{4x}{ x - 4} = \frac{x}{2x} \times \frac{1}{1} = \frac{1}{2} = 0.5[/tex]
4.
[tex] \frac{5 {x}^{4} {y}^{3} }{x + 3} \div 10 {x}^{2} {y}^{3} = \frac{5 {x}^{4} {y}^{3} }{x + 3} \times \frac{1}{10 {x}^{2} {y}^{3} } = \frac{ {x}^{2} }{x + 3} \times \frac{1}{2} = \frac{ {x}^{2} }{2(x + 3)} = \frac{ {x}^{2} }{2x + 6} [/tex]
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Ответ:
2.
[tex]( \frac{ {a}^{2}b^{3} }{3c ^{5} } ) ^{4} = \frac{ {a}^{8} {b}^{12} }{81 {c}^{20} } [/tex]
3.
[tex] \frac{ {x}^{2} - 4x }{8 {x}^{2} } \div \frac{x - 4}{4x} = \frac{ x(x - 4) }{8 {x}^{2} } \times \frac{4x}{ x - 4} = \frac{x}{2x} \times \frac{1}{1} = \frac{1}{2} = 0.5[/tex]
4.
[tex] \frac{5 {x}^{4} {y}^{3} }{x + 3} \div 10 {x}^{2} {y}^{3} = \frac{5 {x}^{4} {y}^{3} }{x + 3} \times \frac{1}{10 {x}^{2} {y}^{3} } = \frac{ {x}^{2} }{x + 3} \times \frac{1}{2} = \frac{ {x}^{2} }{2(x + 3)} = \frac{ {x}^{2} }{2x + 6} [/tex]