[tex]x^{2} + 4x + 4 =0\\(x+2)^{2} =0\\x = -2[/tex]
Ответ: x1 = -2 x2=-2
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[tex]x^{2} + 4x + 4 =0\\(x+2)^{2} =0\\x = -2[/tex]
Ответ: x1 = -2 x2=-2