[tex]\displaystyle 1)\frac{x^4-10x^2+9}{x+3}=0,x\neq -3\\ \\\frac{x^4-x^2-9x^2+9}{x+3}=0\\ \\\frac{x^2(x^2-1)-9(x^2-1)}{x+3}=0\\ \\\frac{(x^2-1)(x^2-9)}{x+3}=0\\ \\\frac{(x-1)(x+1)(x-3)(x+3)}{x+3}=0\\ \\(x-1)(x+1)(x-3)=0\\x-1=0,x+1=0,x-3=0\\x_1=-1,x_2=1,x_3=3\\\\2)\frac{2x^2-5x+2}{x^2-4}=3,x\neq -2,x\neq 2\\\\\frac{2x^2-x-4x+2}{(x-2)(x+2)}=3\\ \\\frac{x(2x-1)-2(2x-1)}{(x-2)(x+2)}=3\\ \\\frac{(2x-1)(x-2)}{(x-2)(x+2)}=3\\ \\\frac{2x-1}{x+2}=3\\ \\2x-1=3(x+2)\\2x-1=3x+6\\2x-3x=6+1\\-x=7\\x=-7[/tex]
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[tex]\displaystyle 1)\frac{x^4-10x^2+9}{x+3}=0,x\neq -3\\ \\\frac{x^4-x^2-9x^2+9}{x+3}=0\\ \\\frac{x^2(x^2-1)-9(x^2-1)}{x+3}=0\\ \\\frac{(x^2-1)(x^2-9)}{x+3}=0\\ \\\frac{(x-1)(x+1)(x-3)(x+3)}{x+3}=0\\ \\(x-1)(x+1)(x-3)=0\\x-1=0,x+1=0,x-3=0\\x_1=-1,x_2=1,x_3=3\\\\2)\frac{2x^2-5x+2}{x^2-4}=3,x\neq -2,x\neq 2\\\\\frac{2x^2-x-4x+2}{(x-2)(x+2)}=3\\ \\\frac{x(2x-1)-2(2x-1)}{(x-2)(x+2)}=3\\ \\\frac{(2x-1)(x-2)}{(x-2)(x+2)}=3\\ \\\frac{2x-1}{x+2}=3\\ \\2x-1=3(x+2)\\2x-1=3x+6\\2x-3x=6+1\\-x=7\\x=-7[/tex]