Ответ:

[tex]\displaystyle\ \frac{9}{8}\cdot \left(8-2\ \frac{\ 2}{15}\cdot 3\ \frac{\ 1}{8}\right)[/tex]

Как и просил, разложу на действия:

• [tex]\displaystyle2\frac{2}{15} *3\frac{1}{8} =\frac{32}{15} *\frac{25}{8}=\frac{32*5}{25*8}=\frac{800}{120} =\frac{20*40}{3*40}=\frac{20}{3} =6\frac{2}{3}[/tex]

• [tex]\displaystyle8-6\frac{2}{3} =8-6-\frac{2}{3} =2-\frac{2}{3} =\frac{2*3}{3}-\frac{2}{3}=\frac{6}{3}-\frac{2}{3} =\frac{4}{3}=1\frac{1}{3}[/tex]

• [tex]\displaystyle\frac{9}{8} *1\frac{1}{3} =\frac{9}{8} *\frac{1+1*3}{3} =\frac{9}{8}*\frac{4}{3}=\frac{9*4}{8*3}=\frac{36}{24}=\frac{3*12}{2*12}=\frac{3}{2}= 1\frac{1}{2}[/tex]

И того ответ:

[tex]\displaystyle\displaystyle\ \frac{9}{8}\cdot \left(8-2\ \frac{\ 2}{15}\cdot 3\ \frac{\ 1}{8}\right)=1\frac{1}{2}[/tex]