Ответ: -0,2

[tex] {(4x - 3y)}^{2} + (4x + 3y)(3y - 4x) - 6y(3y - 5x + 5) = {16x}^{2} - 24xy + {9y}^{2} + {9y}^{2} - {16x}^{2} - {18y}^{2} + 30xy - 30y = 6xy - 30y = 6y(x - 5)[/tex]

И при х=3 у=1/60 будет

[tex]6y(x - 5) = 6 \times \frac{1}{60} (3 - 5) = \frac{1}{10} \times ( - 2) = - \frac{1}{5} = - 0.2[/tex]