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CRANBERRY576M
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August 2022
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8-ОЙ КЛАСС. ПОДРОБНОЕ РЕШЕНИЕ, ПОЖАЛУЙСТА
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physicsonelove
По теореме косинусов:
AC^2 = AB^2 + BC^2 - 2*AB*BC*cosB
(4*√5)^2 = 5^2 + 5^2 - (2*5*5*(-x/5))
16*5 = 25 + 25 + 2*5*5*(x/5)
80 = 50 + 10x
10x = 80 - 50 = 30
x = 3
Ответ: х = 3
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Answers & Comments
AC^2 = AB^2 + BC^2 - 2*AB*BC*cosB
(4*√5)^2 = 5^2 + 5^2 - (2*5*5*(-x/5))
16*5 = 25 + 25 + 2*5*5*(x/5)
80 = 50 + 10x
10x = 80 - 50 = 30
x = 3
Ответ: х = 3