[tex]1. \sqrt{\frac{3}{4}} = \frac{\sqrt{3} }{2} \\2. \frac{\frac{\sqrt{3} }{2}}{\frac{1}{2} } = \sqrt{3}\\3. \frac{1}{tg \beta } = \frac{1}{\sqrt{3} } = \frac{\sqrt{3} }{3}[/tex]

Ответ:

[tex]sin\beta =\frac{\sqrt{3} }{2} \\tg\beta =\sqrt{3}\\ ctg\beta = \frac{\sqrt{3} }{3}[/tex]