3BaCl2+Al2(SO4)3=3BaSO4↓+2AlCl3
n(Al2(SO4)3)=200*0.104/342=0.06 моль
m(BaSO4)=0.06*3*233=41.94 г
вроде так
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3BaCl2+Al2(SO4)3=3BaSO4↓+2AlCl3
n(Al2(SO4)3)=200*0.104/342=0.06 моль
m(BaSO4)=0.06*3*233=41.94 г
вроде так