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aliserbajgendzaev
@aliserbajgendzaev
July 2022
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#819
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tofiq89
819.1
1)1+5/(1+×)=(6+×)/(1+×)
2)4/((6+×/1+×))=(4+4×)/6+×)
3)1+(4+4×)/(6+×)=(5(×+2))/(6+×)
4)5/((5(×+2)/(6+×))=(6+×)/(×+2)
5) 2=(6+×)/(×+2)
×=2
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Answers & Comments
1)1+5/(1+×)=(6+×)/(1+×)
2)4/((6+×/1+×))=(4+4×)/6+×)
3)1+(4+4×)/(6+×)=(5(×+2))/(6+×)
4)5/((5(×+2)/(6+×))=(6+×)/(×+2)
5) 2=(6+×)/(×+2)
×=2