[tex]\displaystyle\bf\\1)\\\\18\frac{1}{4} +2\frac{1}{6} =\Big(18+2\Big)+\Big(\frac{1}{4} +\frac{1}{6} \Big)=20+\frac{3+2}{12} =20\frac{5}{12} \\\\2)\\\\20\frac{5}{12} :1\frac{1}{4}=\frac{245}{12} :\frac{5}{4}= \frac{245}{12} \cdot\frac{4}{5}=\frac{49}{3} =16\frac{1}{3}[/tex]