Ответ:
дано
n(CO2) = 0.5 mol
---------------------
V(C2H6)-?
V(O2)-?
2C2H6+7O2-->4CO2+6H2O
2n(C2H6) = 4n(CO2)
n(C2H6) = 2*0.5 / 4 = 0.25 mol
V(C2H6) = n*Vm = 0.25 * 22.4 = 5.6 L
7n(O2) = 4n(CO2)
n(O2) = 7 * 0.5 / 4 = 0.875 mol
V(O2) = n*Vm = 0.875 * 22.4 = 19.6 L
ответ 5.6 л , 19.6 л
Объяснение:
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Answers & Comments
Ответ:
дано
n(CO2) = 0.5 mol
---------------------
V(C2H6)-?
V(O2)-?
2C2H6+7O2-->4CO2+6H2O
2n(C2H6) = 4n(CO2)
n(C2H6) = 2*0.5 / 4 = 0.25 mol
V(C2H6) = n*Vm = 0.25 * 22.4 = 5.6 L
7n(O2) = 4n(CO2)
n(O2) = 7 * 0.5 / 4 = 0.875 mol
V(O2) = n*Vm = 0.875 * 22.4 = 19.6 L
ответ 5.6 л , 19.6 л
Объяснение: