Ответ:

а)3х²+5х-2=3(x+2)(x-1/3)=(x+2)(3x-1)

D=25+24=49; x1=(-5-7)/6=-2; x2=(-5+7)/6=1/3

(7x+14)/(3x²+5x-2)=7(x+2)/(x+2)(3x-1)=7/(3x-1)

b) 3x²-7x+2=3(x-1/3)(x-2)=(3x-1)(x-2)

D=49-24=25; x1=(7-5)/6=1/3;x2=(7+5)/6=2

(9x²-16)/(3x²-7x+2)=(3x-4)(3x+4)/(3x-1)(x-2)

в)11у²-4у³+3у=у(-4у²+11у+3)=4y(y-3)(y+1/4)=y(y-3)(4y+1)

D=121+48=169: x1=(-11-13)/(-8)=3; x2=(-11+13)/(-8=-1/4

D1=49+32=81; y1=(7-9)/8=-1/4; y2=(7+9)/8=2

4y²-7y-2=4(y+1/4)(y-2)=(4y+1)(y-2)

(4y²-7y-2)/11y²-4y³+3y=(4y+1)(y-2)/y(y-3)(4y+1)=(y-2)/y(y-3)