Verified answer

[tex]2 {x}^{2} - 5x + 2 = 0 \\ a = 2 \\ b = - 5 \\ c = 2 \\ D = {b}^{2} - 4ac = ( - 5) {}^{2} - 4 \times 2 \times 2 = 25 - 16 = 9\\ x_{1} = \frac{5 - 3}{2 \times 2} = \frac{2}{4} = 0.5\\ x_{2} = \frac{5 + 3}{2 \times 2} = \frac{8}{4} = 2[/tex]

Ответ: 1)