Ответ:
[tex]a) \: (xy - z)(xy + z)[/tex]
[tex]б) \: (ab - 4)(ab + 4)[/tex]
[tex]в) \: {x}^{2} + 2xy + {y}^{2} - {z}^{2} [/tex]
[tex]г) \: 9 {a}^{2} + 6a - 3[/tex]
[tex]д) \: ( y- 5z {)}^{2} [/tex]
[tex]е) \: (1 - 6p {)}^{2} [/tex]
Объяснение:
[tex]a) \: {x}^{2} {y}^{2} - {z}^{2} = (xy) {}^{2} - {z}^{2} = (xy - z)(xy + z)[/tex]
[tex]б) \: {a}^{2} {b}^{2} - 16 = (ab {)}^{2} - {4}^{2} = (ab - 4)(ab + 4)[/tex]
[tex]в) \: {x}^{2} + 2xy + {y}^{2} - {z}^{2} = {x}^{2} + 2xy + {y}^{2} - {z}^{2}[/tex]
[tex]г) \: (3a + 1 {)}^{2} - 4 = {9}^{2} + 6a + 1 - 4 = 9 {a}^{2} + 6a - 3[/tex]
[tex]д) \: {y}^{2} + 25 {z}^{2} - 10yz = {y}^{2} - 10yz + 25 {z}^{2} = (y - 5z {)}^{2} [/tex]
[tex]е) \: 1 - 12p + 36 {p}^{2} = {1}^{2} - 2 \times 1 \times 6p + {6}^{2} {p}^{2} = {1}^{2} - 2 \times 1 \times 6p + (6p {)}^{2} = (1 - 6p {)}^{2} [/tex]
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Ответ:
[tex]a) \: (xy - z)(xy + z)[/tex]
[tex]б) \: (ab - 4)(ab + 4)[/tex]
[tex]в) \: {x}^{2} + 2xy + {y}^{2} - {z}^{2} [/tex]
[tex]г) \: 9 {a}^{2} + 6a - 3[/tex]
[tex]д) \: ( y- 5z {)}^{2} [/tex]
[tex]е) \: (1 - 6p {)}^{2} [/tex]
Объяснение:
[tex]a) \: {x}^{2} {y}^{2} - {z}^{2} = (xy) {}^{2} - {z}^{2} = (xy - z)(xy + z)[/tex]
[tex]б) \: {a}^{2} {b}^{2} - 16 = (ab {)}^{2} - {4}^{2} = (ab - 4)(ab + 4)[/tex]
[tex]в) \: {x}^{2} + 2xy + {y}^{2} - {z}^{2} = {x}^{2} + 2xy + {y}^{2} - {z}^{2}[/tex]
[tex]г) \: (3a + 1 {)}^{2} - 4 = {9}^{2} + 6a + 1 - 4 = 9 {a}^{2} + 6a - 3[/tex]
[tex]д) \: {y}^{2} + 25 {z}^{2} - 10yz = {y}^{2} - 10yz + 25 {z}^{2} = (y - 5z {)}^{2} [/tex]
[tex]е) \: 1 - 12p + 36 {p}^{2} = {1}^{2} - 2 \times 1 \times 6p + {6}^{2} {p}^{2} = {1}^{2} - 2 \times 1 \times 6p + (6p {)}^{2} = (1 - 6p {)}^{2} [/tex]