Ответ:
[tex]\displaystyle\frac{3^0*9^-^5}{81^-^3*3} =\frac{1}{81^-^3*3*9^5} =\frac{81^3}{3*9^5} =\frac{3^1^1}{9^5} =\frac{3^1^1}{3^1^0} =3^{11-10} =3^1=3[/tex]
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Ответ:
[tex]\displaystyle\frac{3^0*9^-^5}{81^-^3*3} =\frac{1}{81^-^3*3*9^5} =\frac{81^3}{3*9^5} =\frac{3^1^1}{9^5} =\frac{3^1^1}{3^1^0} =3^{11-10} =3^1=3[/tex]
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