Объяснение:
2)
[tex] \frac{ {x}^{3} {y}^{15} }{x {y}^{6} } = \frac{ {x}^{2} {y}^{9} }{1} = {x}^{2} {y}^{9} [/tex]
3)
- (2x - 6y) = - 2x + 6y
- (2m + 3m) = - 2m - 3m = - 5m
4)
5(6x - 7m - 11) = 30x - 35m - 55
5)
(x - 4)(5 - 2x) = 5x - 2x² - 20 + 8x = - 2x² + 13x - 20
6(2x + 3) = 4(x - 7)
12x + 18 = 4x - 28
12x - 4x = - 28 - 18
8x = - 46 /:8
x = - 5,75
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Verified answer
Объяснение:
2)
[tex] \frac{ {x}^{3} {y}^{15} }{x {y}^{6} } = \frac{ {x}^{2} {y}^{9} }{1} = {x}^{2} {y}^{9} [/tex]
3)
- (2x - 6y) = - 2x + 6y
- (2m + 3m) = - 2m - 3m = - 5m
4)
5(6x - 7m - 11) = 30x - 35m - 55
5)
(x - 4)(5 - 2x) = 5x - 2x² - 20 + 8x = - 2x² + 13x - 20
6(2x + 3) = 4(x - 7)
12x + 18 = 4x - 28
12x - 4x = - 28 - 18
8x = - 46 /:8
x = - 5,75