[tex]\displaystyle\bf\\(2k+3)^{2} -(2k-3)^{2} =(2k+3+2k-3)\cdot\Big[2k+3-(2k-3)\Big]=\\\\=4k\cdot(2k+3-2k+3)=4k\cdot6=24k[/tex]
24k делится на 24
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[tex]\displaystyle\bf\\(2k+3)^{2} -(2k-3)^{2} =(2k+3+2k-3)\cdot\Big[2k+3-(2k-3)\Big]=\\\\=4k\cdot(2k+3-2k+3)=4k\cdot6=24k[/tex]
24k делится на 24