Ответ:-25/x⁶-3/√x
Объяснение:
f'(x)=-25/x⁶-6/(2√x)=-25/x⁶-3/√x
(√x)'=1/(2√x)
(xⁿ)'=n*xⁿ⁻¹
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Ответ:-25/x⁶-3/√x
Объяснение:
f'(x)=-25/x⁶-6/(2√x)=-25/x⁶-3/√x
(√x)'=1/(2√x)
(xⁿ)'=n*xⁿ⁻¹