sin^2(9pi/8+a)-sin^2(15 pi/8+a) Помогите пожалуйста. Created by Laki333. algebra-ru

8+a) Помогите пожалуйста...

July 2022 1 1 Report

sin^2(9pi/8+a)-sin^2(15 pi/8+a) Помогите пожалуйста

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sedinalana Sin^2(9pi/8+a)-sin^2(15 pi/8+a) =
=(Sin(9pi/8+a)-sin(15 pi/8+a) )(Sin(9pi/8+a)+sin(15 pi/8+a) )
=2sin(-3π/8)cos3π *2sin(3π/2+a)=-2sin(3π/8)*(-2cosa=2sin(3π/4)cosa=
=2sin(π/4)cosa=√2cosa

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