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Emma111111
@Emma111111
August 2022
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Преобразуйте в произведение :
1) 49p^2 - q^2
Разложите на множители :
2) 1/8a^3 + b^3
3)4n^2 - 9
4)27-x^3
5)X+5x^2 - y - 5y^2
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Answers & Comments
1401Tamara
1) 49p^2 - q^2 = (7p -q)(7p+q)
2) 1/8a^3 + b^3 = (1/2a+b)(1/4a^2 - 1/2ab + b^2)
3)4n^2 - 9 = (2n-3)(2n+3)
4)27-x^3 = ((3-x)(9+3x+x^2)
5)X+5x^2 - y - 5y^2 = (x-y) + 5(x^2 - y^2) = (x-y) + 5(x - y)(x+y) =
= (x-y)(1-5(x+y)) = (x-y)(1 - 5x - 5y)
1 votes
Thanks 3
Emma111111
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litanalove
у вас ошибка будет +5х+5у
litanalove
1) (7p-q)(7p+q)
2) 1/8=1/2^3
(1/2a+b)(1/4a^2-1/2ab+b^2)
3) (2n-3)(2n+3)
4) 3^3-x^3=(3-x)(9+3x+x^2)
5) (x-y)+5(x^2-y^2)=
(x-y)+5(x-y)(x+y)=(x-y)(1+5x+5y)
2 votes
Thanks 2
Emma111111
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Answers & Comments
2) 1/8a^3 + b^3 = (1/2a+b)(1/4a^2 - 1/2ab + b^2)
3)4n^2 - 9 = (2n-3)(2n+3)
4)27-x^3 = ((3-x)(9+3x+x^2)
5)X+5x^2 - y - 5y^2 = (x-y) + 5(x^2 - y^2) = (x-y) + 5(x - y)(x+y) =
= (x-y)(1-5(x+y)) = (x-y)(1 - 5x - 5y)
2) 1/8=1/2^3
(1/2a+b)(1/4a^2-1/2ab+b^2)
3) (2n-3)(2n+3)
4) 3^3-x^3=(3-x)(9+3x+x^2)
5) (x-y)+5(x^2-y^2)=
(x-y)+5(x-y)(x+y)=(x-y)(1+5x+5y)