[tex]\displaystyle \left \{ {{5-5(0,2m-2x)=3(3x+2)+2m} \atop {4(x-5m)-(2x+m)=10-2(2x+m)}} \right. \\\\\left \{ {{m=\frac{1}{3}x-\frac{1}{3} } \atop {4(x-5m)-(2x+m)=10-2(2x+m)}} \right.\\ \\4(x-5(\frac{1}{3}x-\frac{1}{3}))-(2x+\frac{1}{3}x-\frac{1}{3})=10-2(2x+\frac{1}3}x-\frac{1}{3})\\ \\x=-11\\ \\m=\frac{1}{3}*(-11)-\frac{1}3}\\ \\m=-4\\ (m,x)=(-4,-11)[/tex]